SELECT table_name, table_type, table_comment FROM information_schema.TABLES WHERE TABLE_SCHEMA ='db_name'
查询表字段(字段名,字段类型,字段注释)
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SELECT column_name, DATA_TYPE as column_type, IF(COLUMN_COMMENT ISNULLOR COLUMN_COMMENT='', COLUMN_NAME, COLUMN_COMMENT) AS column_comment FROM information_schema.COLUMNS WHERE TABLE_NAME='table_name'
oracle元数据
查询表及视图(表名,表/视图,表注释)
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select do.object_name as table_name, do.object_type as table_type, utc.comments as table_remark from dba_objects do leftjoin user_tab_comments utc on utc.table_name = do.object_name where owner ='db_name' and object_type in ('TABLE','VIEW')
SELECT DISTINCT(atc.column_name) as column_name, atc.data_type as column_type, ucc.comments as column_comment FROM all_tab_cols atc leftjoin user_col_comments ucc on atc.column_name = ucc.column_name where atc.table_name ='TABLE_NAME' and ucc.table_name ='TABLE_NAME'; -- TABLE_NAME 大写哈,另外此sql 不一定能查出来字段注释;
select ut.COLUMN_NAME,--字段名称 uc.comments,--字段注释 ut.DATA_TYPE,--字典类型 ut.DATA_LENGTH,--字典长度 ut.NULLABLE--是否为空 from all_tab_columns ut innerJOIN all_col_comments uc on ut.TABLE_NAME = uc.table_name and ut.COLUMN_NAME = uc.column_name where ut.TABLE_NAME='TABLE_NAME' orderby ut.column_name -- 7.16补充 这种可以查出来
select t1.table_name, t1.table_type, t2.table_remark from (select sys.name as table_name, (CASE sys.xtype WHEN'U' THEN'TABLE' ELSE'VIEW'END)as table_type from sysobjects sys where sys.xtype in ('U','V')) t1 leftjoin (SELECT CONVERT(nvarchar(50),ISNULL(A.[name], '')) as table_name, CONVERT(nvarchar(50),ISNULL(C.[value], '')) as table_remark FROM sys.tables A LEFTJOIN sys.extended_properties C ON C.major_id = A.object_id WHERE C.minor_id=0 ) t2 on t1.table_name = t2.table_name -- 此sql 不能查出视图注释,若你知道其他的办法可留言告知!
select t1.column_name, t2.column_type, t1.column_comment from (SELECT B.name as column_name, C.value as column_comment FROM sys.tables A INNERJOIN sys.columns B ON B.object_id = A.object_id LEFTJOIN sys.extended_properties C ON C.major_id = B.object_id AND C.minor_id = B.column_id WHERE A.name ='table_name')t1 leftjoin (select column_name, data_type as column_type from information_schema.columns t where t.table_name='table_name') t2 on t1.column_name = t2.column_name